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Here's an Interesting Question.

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Blackcrow
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Posted - 2005/08/02 :  12:26:43  Show profile Send a private message
I think i should send this one of to SKY's braniac Science Abuse, thats if there was a way they could find out.


If i could run down the motorway at the same speed the cars were going.

And could keep going without stoping from Reading to London, how much would i need to eat in calories to keep going.

Because if anybody has seen "The Flash", they should remember that scene where he ate 5 12" Pizzas.





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Underloop
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Posted - 2005/08/02 :  12:58:42  Show profile  Send a private message  Visit Underloop's homepage
OK, after a bit of googling and some throwing about of equations, I have derived the following equation relating distance, speed and calories (it relies on the fact that calories burnt against velocity remains constant at high velocities, which if these speeds were possible I doubt it would be linear)

E = 60*d*(1.0875 +0.7/v)

Where E is the energy burnt in calories
d is the distance travelled in km
v is the velocity in km/h

Working on the speed limit on a motorway (70mph = 112.7 km/h) and the distance from reading to london being 60.67 km (looked up on the net) then the total calories burnt for this journey would be 3981.3 kCal!!!

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"We don't stop playing because we grow old;
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"We don't stop playing because we grow old;
we grow old because we stop playing."
- George Bernard Shaw


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Squishy Star
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Posted - 2005/08/02 :  13:59:42  Show profile  Send a private message  Visit Squishy Star's homepage
oh - my - god ! wtf?!

xtremely smart question and an xtremely smart a** answer especially when it's 8 in the morning during summer holidays!! =O


http://www.myspace.com/20255908


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Underloop
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Posted - 2005/08/02 :  14:05:16  Show profile  Send a private message  Visit Underloop's homepage
Would it help if I mentioned that I have 2 months of research left before I start writing up my PhD and this time next year I'l be Dr. Under(smart arse)loop :-P

Oh, the accuracy isn't spot in in the above equation as it relied on fitting some data which I googled across and the fitting equation isn't 100% spot on..... but it gives you a good idea lol

_________________________________
"We don't stop playing because we grow old;
we grow old because we stop playing."
- George Bernard Shaw


__________________________________
"We don't stop playing because we grow old;
we grow old because we stop playing."
- George Bernard Shaw


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Blackcrow
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Posted - 2005/08/02 :  14:47:06  Show profile  Send a private message  Visit Blackcrow's homepage
I am Blown away.

You are very intelligent underloop, i dont understand the equation very well thou.

what does * mean in your context, i dont understand equations that well......

not very well........really.......at all.






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Squishy Star
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Posted - 2005/08/02 :  14:56:09  Show profile  Send a private message  Visit Squishy Star's homepage
lol! i'm pretty sure the " * " means multiplication... =)

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Underloop
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Posted - 2005/08/02 :  15:07:08  Show profile  Send a private message  Visit Underloop's homepage
sorry, * is the same as multiply - usually used when typing as its easy to get confused with the letter x which is used as a variable sometimes

I derived the equation from several sources.

I can't find the data I fitted, but basically it was a linear relationship (that is a straight line when plotted against each other) of running speed against calories burnt per minute, and gave:

cal/min = 1.0875v + 0.7 (where 1.0875 and 0.7 are simply constants and v is velocity - this equation is based on the equation of a line which is y=mx+c which you may know from GCSE maths?)

velocity, v is distance divided by time (v = 60d/t) (the 60 is to convert minutes into hours so all the time units are in hours) or rearranging it t=60d/v

so the left handside of the first equation is the same as Ev/60d (where E is energy in calories).

Substituting the 2 together we get

Ev/60d = 1.0875v + 0.7

and rearanging

E = 60d(1.0875v + 0.7)/v

Yes, its true I am a closet geek!

_________________________________
"We don't stop playing because we grow old;
we grow old because we stop playing."
- George Bernard Shaw


__________________________________
"We don't stop playing because we grow old;
we grow old because we stop playing."
- George Bernard Shaw


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Edited by - Underloop on 2005/08/02 15:10:19
Squishy Star
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Posted - 2005/08/02 :  16:19:57  Show profile  Send a private message  Visit Squishy Star's homepage
i really want to get into the Medical Field, would love to be a surgeon or something but what's giving me second thoughts of having to go to school for years and years is...the lack of time i'll have to enjoy myself and going to raves. haha but i guess it's definitely possible to be a "closet geek" and still have just as much fun as those who don't have a desire to achieve higher...
(harsh!) but that's not my point.

and yea...the equation, y=mx+c, looks really familiar... >.<
y=ax^2+bx+c ...^^ looks like something that'd have to do with lines and slopes...

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Underloop
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Posted - 2005/08/02 :  16:57:50  Show profile  Send a private message  Visit Underloop's homepage
Heh, sorry I'm not a medical doctor..... studying for a PhD in Mechanical Engineering. Specialising in dynamics and vibration at the moment. Although students have to work hard, we do also play just as hard! Stick with what your heart tells you

y=ax^2+bx+c is the equation of a parabola


_________________________________
"We don't stop playing because we grow old;
we grow old because we stop playing."
- George Bernard Shaw


__________________________________
"We don't stop playing because we grow old;
we grow old because we stop playing."
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Squishy Star
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Posted - 2005/08/02 :  17:04:15  Show profile  Send a private message  Visit Squishy Star's homepage
i know u're not a medical doctor...but i was just saying that I'd like to become one but anyways...dynamics and vibration?? explain

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steve O
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Posted - 2005/08/02 :  17:23:29  Show profile  Send a private message
quote:
Originally posted by Underloop:

velocity, v is distance divided by time




HAHAA! Velocity is displacement divided by time. Vector quantities man!

Sorry for being pedantic lol!



'BCN style'


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Hard2Get
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Posted - 2005/08/02 :  17:28:48  Show profile  Send a private message  Visit Hard2Get's homepage
quote:
Originally posted by Squishy Star:
oh - my - god ! wtf?!



My thoughts entirely :)




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Underloop
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Posted - 2005/08/02 :  20:40:29  Show profile  Send a private message  Visit Underloop's homepage
quote:
Originally posted by steve O:
quote:
Originally posted by Underloop:

velocity, v is distance divided by time




HAHAA! Velocity is displacement divided by time. Vector quantities man!

Sorry for being pedantic lol!

'BCN style'



heh, errmm yeah *blush* I should've said speed I guess as you can't travel reading to london on foot as the crow flies, or maybe even modulus of displacement. I was good though and used SI units

Squishy: Sorry, so used to people assuming when i say Dr that I can cure their life threatening illnesses.... they get worried when I take a torque wrench out.

Dynamics and vibration.... basically studying how things behave when they're being shaken. Natural frequencies and all that. The main thing I am looking at right now is how aircraft panels react to extremly high levels of noise such as that produced by fighter jet engines placed right next to it. By high levels we're talking up to about 185dB (for examples of sound levels check the table halfway down at http://www.nonoise.org/quietnet/sienc/soundlev.htm).

_________________________________
"We don't stop playing because we grow old;
we grow old because we stop playing."
- George Bernard Shaw


__________________________________
"We don't stop playing because we grow old;
we grow old because we stop playing."
- George Bernard Shaw


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whittle1
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Posted - 2005/08/02 :  22:13:57  Show profile  Send a private message  Visit whittle1's homepage
quote:
Originally posted by Underloop:
sorry, * is the same as multiply - usually used when typing as its easy to get confused with the letter x which is used as a variable sometimes

I derived the equation from several sources.

I can't find the data I fitted, but basically it was a linear relationship (that is a straight line when plotted against each other) of running speed against calories burnt per minute, and gave:

cal/min = 1.0875v + 0.7 (where 1.0875 and 0.7 are simply constants and v is velocity - this equation is based on the equation of a line which is y=mx+c which you may know from GCSE maths?)

velocity, v is distance divided by time (v = 60d/t) (the 60 is to convert minutes into hours so all the time units are in hours) or rearranging it t=60d/v

so the left handside of the first equation is the same as Ev/60d (where E is energy in calories).

Substituting the 2 together we get

Ev/60d = 1.0875v + 0.7

and rearanging

E = 60d(1.0875v + 0.7)/v

Yes, its true I am a closet geek!

_________________________________
"We don't stop playing because we grow old;
we grow old because we stop playing."
- George Bernard Shaw



Wow i wish i was smart at maths
Only got a D in my GCSE, just missed a C
I'm still annoyed at that to this day, does not look good on my CV

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lucificifus
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Posted - 2005/08/02 :  22:36:06  Show profile  Send a private message  Visit lucificifus's homepage
I'm so drinking expensive wine an watching a german version of "Jerry Springer"

wooooooooooooooooooooooooooooooooooooooo--

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pump tha selectah!


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pump tha selectah!




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mark-ireland
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Posted - 2005/08/02 :  22:53:26  Show profile  Send a private message  Visit mark-ireland's homepage
quote:
OK, after a bit of googling and some throwing about of equations, I have derived the following equation relating distance, speed and calories (it relies on the fact that calories burnt against velocity remains constant at high velocities, which if these speeds were possible I doubt it would be linear)

E = 60*d*(1.0875 +0.7/v)

Where E is the energy burnt in calories
d is the distance travelled in km
v is the velocity in km/h

Working on the speed limit on a motorway (70mph = 112.7 km/h) and the distance from reading to london being 60.67 km (looked up on the net) then the total calories burnt for this journey would be 3981.3 kCal!!!


Someone has a bit too much time one their hands :P

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