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Lilley
Advanced Member
Australia
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 Posted - 2010/02/12 : 15:08:47
Oh well, whatever. I'm sure we'll all be willing to pitch in if you have a problem.
The silly mistakes i referred to were the ones you asked me about.
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Rayovac
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Posted - 2010/02/12 : 20:33:01
quote:
Originally posted by Lilley:
Oh well, whatever. I'm sure we'll all be willing to pitch in if you have a problem.
The silly mistakes i referred to were the ones you asked me about.
Well OK,
"Evaluate |a plus b minus c|, given a = 5, b = -3, and c = -2."
The answer I get is 6. However the only available answers are -4, 4, 10, and 0.
-4 is impossible as this problem is an absolute value.
Not sure about 4.
10 can be achieved if the subtraction aspect is tossed out and 5, 3, and 2 are added. That's just... no.
Not sure about 0.
Why is that this forum doesn't support plus signs anyway?
Cheers.
Scratch that, I was applying a rule where I shouldn't have... again. -_-
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Edited by - Rayovac on 2010/02/12 20:45:58 |
Lilley
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Posted - 2010/02/13 : 01:51:25
huh? I was just saying, do it however you want to and think is best, but at the end of the day i'm sure all of us will be willing to help.
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Rayovac
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Posted - 2010/02/18 : 23:31:51
quote:
Originally posted by Lilley:
huh? I was just saying, do it however you want to and think is best, but at the end of the day i'm sure all of us will be willing to help.
Ok :).
Well, here's another one. I'm supposed to simplify 18 - 2[x + (x - 5)]. Here's what I've done so far:
18 - 2[x + (x - 5)]
18 - 2[x + -5x]
18 - 2[-4x]
18 - 2
The last one is where I'm stuck. What's thrown me off is the ...x + (x... part. Maybe I'm oversimplifying? Maybe I forget an important detail again? Gaaaaaah.
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tru bass
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United Kingdom
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Posted - 2010/02/18 : 23:46:36
quote:
Originally posted by Rayovac:
quote:
Originally posted by Lilley:
huh? I was just saying, do it however you want to and think is best, but at the end of the day i'm sure all of us will be willing to help.
Ok :).
Well, here's another one. I'm supposed to simplify 18 - 2[x + (x - 5)]. Here's what I've done so far:
18 - 2[x + (x - 5)]
18 - 2[x + -5x]
18 - 2[-4x]
18 - 2
The last one is where I'm stuck. What's thrown me off is the ...x + (x... part. Maybe I'm oversimplifying? Maybe I forget an important detail again? Gaaaaaah.
edit: scratch that, i just noticed the + :s
edit edit: the last edit was probably the worst piece of maths i have ever seen...
18 - 2(x + (x - 5))
18 - 2(x + x - 5)
18 - 2(2x - 5)
18 - 4x + 10
28 - 4x
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Edited by - tru bass on 2010/02/21 19:52:47 |
Rayovac
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United States
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Posted - 2010/02/19 : 00:23:45
quote:
Originally posted by tru bass:
quote:
Originally posted by Rayovac:
quote:
Originally posted by Lilley:
huh? I was just saying, do it however you want to and think is best, but at the end of the day i'm sure all of us will be willing to help.
Ok :).
Well, here's another one. I'm supposed to simplify 18 - 2[x + (x - 5)]. Here's what I've done so far:
18 - 2[x + (x - 5)]
18 - 2[x + -5x]
18 - 2[-4x]
18 - 2
The last one is where I'm stuck. What's thrown me off is the ...x + (x... part. Maybe I'm oversimplifying? Maybe I forget an important detail again? Gaaaaaah.
edit: scratch that, i just noticed the + :s
18 - 2x + 2x - 1
18 - 4x - 10
8 - 4x
Son of a beech tree, that was actually one of the approaches I had taken. Just the addition sign had thrown me off there too.
Major thanks and cheers again.
Edit: Wrong. :( The program says it's 28 - 4x, which means the addition sign was kept...
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Edited by - Rayovac on 2010/02/19 00:32:53 |
Lilley
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Australia
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Posted - 2010/02/20 : 23:38:22
18 - 2[x + (x - 5)]
you probably know this, but its order of operations.
()
*/
+-
there should be something between the parenthesis and multiplication level, just cant remember it atm
so you start with the innermost parenthesis, simplify, and then work outwards, removing the () as you go. For what its worth, x - 5 is a simple as it can get, dont need to do anything other than remove the brackets.
that gives 18 - 2(x + x - 5) or 18 - 2(2x - 5). that should be a starting point, and remember to be careful with silly mistakes, expanding of brackets, double negatives being positive, etc.
if you can't work out the next step, it involves removing the brackets - simplifying { -2(2x - 5) }. see how you go.
edit: their answer is correct. I dont know if you realise this, i assume you do but just in case, the -2[x+(x-5)] is the same as -2*[x+(x-5)]
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Edited by - Lilley on 2010/02/20 23:52:00 |
Lilley
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Australia
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Posted - 2010/02/21 : 13:35:25
actually mate, i see your mums point. If your struggling with basic principles such as these and really want to do well in maths I honestly think it would be best for you to get some face to face tutoring.
In the meantime, pm me or d-tor, we would both be willing to help and without trying to be a snob, could probably be more useful in this regard than other people on here. keeping them private simply reduces the chance of wrong info being given (sorry tru bass but your response had so many mistakes that I had trouble following your answer)
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Rayovac
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Posted - 2010/02/21 : 19:43:23
quote:
Originally posted by Lilley:
actually mate, i see your mums point. If your struggling with basic principles such as these and really want to do well in maths I honestly think it would be best for you to get some face to face tutoring.
In the meantime, pm me or d-tor, we would both be willing to help and without trying to be a snob, could probably be more useful in this regard than other people on here. keeping them private simply reduces the chance of wrong info being given (sorry tru bass but your response had so many mistakes that I had trouble following your answer)
Actually it was my idea; both parents have done absolutely squat so far. 
Nonetheless, thanks.
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Edited by - Rayovac on 2010/02/21 19:43:38 |
tru bass
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United Kingdom
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Posted - 2010/02/21 : 19:49:03
quote:
Originally posted by Lilley:
actually mate, i see your mums point. If your struggling with basic principles such as these and really want to do well in maths I honestly think it would be best for you to get some face to face tutoring.
In the meantime, pm me or d-tor, we would both be willing to help and without trying to be a snob, could probably be more useful in this regard than other people on here. keeping them private simply reduces the chance of wrong info being given (sorry tru bass but your response had so many mistakes that I had trouble following your answer)
I see what you mean there haha, it must have been a late night..
bloody hell that is dyer..
an edit is in order.
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tru bass
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Posted - 2010/02/21 : 19:57:01
I apologise for that absolutely diabolical piece of maths before.. I can't understand for the life of me how i managed to be such a ****ing idiot, I might as well give up my life right now seeing as my future is based on maths.. jeeeeeeeeese
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Rayovac
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United States
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Posted - 2010/02/22 : 02:21:05
quote:
Originally posted by tru bass:
I apologise for that absolutely diabolical piece of maths before.. I can't understand for the life of me how i managed to be such a ****ing idiot, I might as well give up my life right now seeing as my future is based on maths.. jeeeeeeeeese
Don't beat yourself up over it :( I mean look at me, I'm way worse off than you. :P
Edit: Here's another one. It's not part of my schoolwork actually, but it's a problem in a reference book I bought and it's driving me batty.
Distribute and combine
Simplify -1/2(-2 + 8s) + 4(3s - 1)
The process in which how they got their answer (8s - 3) has me dumbfounded. I was hoping one (or more) could do it on their own and explain each step in detail.
(I should note that I plan on only using the more private mediums of communications for the serious schoolwork, as odd as it sounds)
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Edited by - Rayovac on 2010/02/22 03:04:15 |
Lilley
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Australia
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Posted - 2010/02/24 : 13:00:40
you do understand algebra dont you? you can only add or subtract like terms. so you can add 5s and 4s to make 9s but you cant add 3e + 6t together. the simplest form of that is 3e + 6t
Anyway.
The process is to expand then simplify
-1/2(-2 + 8s) + 4(3s - 1)
becomes
(-0.5 * -2) + (-0.5 * 8s) + (4 * 3s) + (4 * -1)
simplify
1 + (-4s) + 12s + (-4)
1 - 4s + 12s - 4
group like terms
12s - 4s + 1 - 4
= 8s - 3
If any line of that did not make sense, reply back and we'll try and get this business properly sorted.
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Edited by - Lilley on 2010/02/24 13:01:31 |
Rayovac
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United States
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Posted - 2010/03/11 : 17:52:05
Tom's not online so I'll post this here.
I made some MAJOR progress over the last few days, although I've run into another problem. It's just a bonus problem but I really want to get it solved.
"The sum of the first and third of three consecutive integers is 54. What is the middle integer?
a. 27
b. 31
c. 35
d. 37"
It doesn't specify whether the consecutive integers are even or odd or anything like that, so I'm assuming 1 2 and 3. So I write it out like this:
(x + 1) + (x + 2) + (x + 3) = 54
Simplified: 3x + 6 = 54
Addition property of equality: 3x + 6 - 6 = 54 - 6, which gives 3x = 48
48/3 = 16
So what I get is 17 + 18 + 19 = 54, which is true, but 18 isn't an option. Where did I screw up?
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Lilley
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Australia
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Posted - 2010/03/11 : 21:58:58
quote:
Originally posted by Rayovac:
Tom's not online so I'll post this here.
I made some MAJOR progress over the last few days, although I've run into another problem. It's just a bonus problem but I really want to get it solved.
"The sum of the first and third of three consecutive integers is 54. What is the middle integer?
a. 27
b. 31
c. 35
d. 37"
It doesn't specify whether the consecutive integers are even or odd or anything like that, so I'm assuming 1 2 and 3. So I write it out like this:
(x + 1) + (x + 2) + (x + 3) = 54
Simplified: 3x + 6 = 54
Addition property of equality: 3x + 6 - 6 = 54 - 6, which gives 3x = 48
48/3 = 16
So what I get is 17 + 18 + 19 = 54, which is true, but 18 isn't an option. Where did I screw up?
you screwed up in reading the question. its only the first and third integers that make 54, not all three. 17+ 19 = 36. and yes consecutive means in a row. If it is odd consecutive then 3,5,7,9. if not specified then just the number directly next to it.
Just a hint. instead of (x+1) + (x+2), you can set your reference point (x) to a different number, even make it part of the sequence ie. (x) + (x+1) + (x+2) or (x-1) + (x) + (x+1). this should make things slightly easier.
Hint: there is a really really easy trick to this question if you can spot it. dont waste your time trying to spot it if you cant see it though.
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